Solve the following pair of linear equations | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) To solve the system of equations $x + 2y = -4$ and $3x + 4y = -6$ graphically:$1$. For the first equation $x + 2y = -4$,if $x = 0$,then $y = -2$.

Vedclass · Accepted Answer

$(2, -3)$

Vedclass · Answer

(D) To solve the system of equations $x + 2y = -4$ and $3x + 4y = -6$ graphically:$1$. For the first equation $x + 2y = -4$,if $x = 0$,then $y = -2$. If $y = 0$,then $x = -4$. The line passes through $(0, -2)$ and $(-4, 0)$.$2$. For the second equation $3x + 4y = -6$,if $x = 0$,then $y = -1.5$. If $y = 0$,then $x = -2$. The line passes through $(0, -1.5)$ and $(-2, 0)$.$3$. Solving the equations algebraically: Multiply the first equation by $2$: $2x + 4y = -8$. Subtract this from the second equation: $(3x + 4y) - (2x + 4y) = -6 - (-8)$,which gives $x = 2$.$4$. Substitute $x = 2$ into $x + 2y = -4$: $2 + 2y = -4 \implies 2y = -6 \implies y = -3$.$5$. The intersection point is $(2, -3)$.

Solve the following pair of linear equations in two variables using a graph: $x + 2y = -4$ and $3x + 4y = -6$.

Similar Questions

The solution set of a pair of equations $x+y-1=0$ and $2x+2y-2=0$ is $\ldots \ldots \ldots \ldots$

The graph of the pair of equations $3x + 4y = 10$ and $3x + 4y = 15$ represents:

The graph of the equation $\ldots \ldots \ldots \ldots$ is parallel to the $X$-axis.

Solve the following pair of linear equations in two variables using a graph: $y = 2$,$x + 4y = 10$.

Form the pair of linear equations in the following problems,and find their solutions graphically.
$5$ pencils and $7$ pens together cost ₹ $50$,whereas $7$ pencils and $5$ pens together cost ₹ $46$. Find the cost of one pencil and that of one pen.

Vedclass Test Series

Exam Paper Generator

Online Exam Module